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Log[2 + x*(2 + x)]/2


Integrate[(1 + x)/(2 + 2*x + x^2), x] ==
Log[2 + x*(2 + x)]/2



             1 + x
Integrate[------------, x] == 
                     2
          2 + 2 x + x

Log[2 + x (2 + x)]
------------------
        2

Time to compute: < 0.01 second

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