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((10*x - 6*x^3)/(-1 + x^2)^2 - 3*Log[3*(-1 + x)] + 3*Log[-3*(1 + x)])/16

Integrate[(1 - x^2)^(-3), x] ==
((10*x - 6*x^3)/(-1 + x^2)^2 - 3*Log[3*(-1 + x)] + 3*Log[-3*(1 + x)])/16 

                2 -3
Integrate[(1 - x )  , x] == 

          3
10 x - 6 x
----------- - 3 Log[3 (-1 + x)] + 3 Log[-3 (1 + x)]
       2 2
(-1 + x )
---------------------------------------------------
                        16
Time to compute: 0.05 second
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