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-x + (2*Sin[x])/(Cos[x] - Sin[x])


Integrate[(Sec[2*x] + Tan[2*x])^2, x] ==
-x + (2*Sin[x])/(Cos[x] - Sin[x])



                               2
Integrate[(Sec[2 x] + Tan[2 x]) , x] == 

        2 Sin[x]
-x + ---------------
     Cos[x] - Sin[x]

Time to compute: 0.06 second

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