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E^x - x - Log[2 + E^x]

Integrate[(Exp[2*x] - 2)/(Exp[x] + 2), x] ==
E^x - x - Log[2 + E^x]

          Exp[2 x] - 2
Integrate[------------, x] == 
           Exp[x] + 2

 x                x
E  - x - Log[2 + E ]
Time to compute: 0.01 second
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