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-ArcTanh[x/(2*Sqrt[2])]/(2*Sqrt[2])

Integrate[1/(-8 + x^2), x] ==
-ArcTanh[x/(2*Sqrt[2])]/(2*Sqrt[2]) 

             1
Integrate[-------, x] == 
                2
          -8 + x

             x
-ArcTanh[---------]
         2 Sqrt[2]
-------------------
     2 Sqrt[2]
Time to compute: 0.02 second
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