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-(1/(a*x)) - (b*Log[x])/a^2 + (b*Log[a + b*x])/a^2


Integrate[1/(x^2*(a + b*x)), x] ==
-(1/(a*x)) - (b*Log[x])/a^2 + (b*Log[a + b*x])/a^2



               1
Integrate[------------, x] == 
           2
          x  (a + b x)

   1     b Log[x]   b Log[a + b x]
-(---) - -------- + --------------
  a x        2             2
            a             a

Time to compute: 0.01 second

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