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(a/(a + b*x) + Log[x] - Log[a + b*x])/a^2


Integrate[1/(x*(a + b*x)^2), x] ==
(a/(a + b*x) + Log[x] - Log[a + b*x])/a^2



               1
Integrate[------------, x] == 
                     2
          x (a + b x)

   a
------- + Log[x] - Log[a + b x]
a + b x
-------------------------------
               2
              a

Time to compute: 0.03 second

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