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2^2^2^x

Integrate[2^(2^2^x + 2^x + x)*Log[2]^3, x] ==
2^2^2^x 

             x
            2     x
           2   + 2  + x       3
Integrate[2             Log[2] , x] == 

   x
  2
 2
2
Time to compute: 0.01 second
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