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(3^Sqrt[1 + 2*x]*(-1 + Sqrt[1 + 2*x]*Log[3]))/Log[3]^2

Integrate[3^Sqrt[1 + 2*x], x] ==
(3^Sqrt[1 + 2*x]*(-1 + Sqrt[1 + 2*x]*Log[3]))/Log[3]^2 

           Sqrt[1 + 2 x]
Integrate[3             , x] == 

 Sqrt[1 + 2 x]
3              (-1 + Sqrt[1 + 2 x] Log[3])
------------------------------------------
                       2
                 Log[3]
Time to compute: 0.02 second
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