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1/(6*x^2) - ArcCot[x]/(3*x^3) + Log[x]/3 - Log[1 + x^2]/6


Integrate[ArcCot[x]/x^4, x] ==
1/(6*x^2) - ArcCot[x]/(3*x^3) + Log[x]/3 - Log[1 + x^2]/6



          ArcCot[x]
Integrate[---------, x] == 
              4
             x

                                     2
 1     ArcCot[x]   Log[x]   Log[1 + x ]
---- - --------- + ------ - -----------
   2        3        3           6
6 x      3 x

Time to compute: < 0.01 second

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