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(9*Sin[a*x] + Sin[3*a*x])/(12*a)


Integrate[Cos[a*x]^3, x] ==
(9*Sin[a*x] + Sin[3*a*x])/(12*a)



                  3
Integrate[Cos[a x] , x] == 

9 Sin[a x] + Sin[3 a x]
-----------------------
         12 a

Time to compute: < 0.01 second

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