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ExpIntegralEi[E^(b + a*x)]/a


Integrate[E^E^(b + a*x), x] ==
ExpIntegralEi[E^(b + a*x)]/a



            b + a x
           E
Integrate[E        , x] == 

               b + a x
ExpIntegralEi[E       ]
-----------------------
           a

Time to compute: < 0.01 second

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