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2*a*ArcTanh[x/a] + x*(-2 + Log[-a^2 + x^2])


Integrate[Log[-a^2 + x^2], x] ==
2*a*ArcTanh[x/a] + x*(-2 + Log[-a^2 + x^2])



                2    2
Integrate[Log[-a  + x ], x] == 

            x                  2    2
2 a ArcTanh[-] + x (-2 + Log[-a  + x ])
            a

Time to compute: < 0.01 second

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