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(2*Log[x])/3 - ((3 + 2*x)*Log[3 + 2*x])/(3*x)


Integrate[Log[3 + 2*x]/x^2, x] ==
(2*Log[x])/3 - ((3 + 2*x)*Log[3 + 2*x])/(3*x)



          Log[3 + 2 x]
Integrate[------------, x] == 
                2
               x

2 Log[x]   (3 + 2 x) Log[3 + 2 x]
-------- - ----------------------
   3                3 x

Time to compute: < 0.01 second

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