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Log[1 + (-3 - 2*x)/3]*Log[3 + 2*x] + PolyLog[2, (3 + 2*x)/3]


Integrate[Log[3 + 2*x]/x, x] ==
Log[1 + (-3 - 2*x)/3]*Log[3 + 2*x] + PolyLog[2, (3 + 2*x)/3]



          Log[3 + 2 x]
Integrate[------------, x] == 
               x

        -3 - 2 x                            3 + 2 x
Log[1 + --------] Log[3 + 2 x] + PolyLog[2, -------]
           3                                   3

Time to compute: 0.01 second

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