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-((Log[a + b*x]*Log[1 - (a + b*x)/(2*a)] + PolyLog[2, (a + b*x)/(2*a)])/b)

Integrate[Log[a + b*x]/(a - b*x), x] ==
-((Log[a + b*x]*Log[1 - (a + b*x)/(2*a)] + PolyLog[2, (a + b*x)/(2*a)])/b) 

          Log[a + b x]
Integrate[------------, x] == 
            a - b x

                       a + b x               a + b x
  Log[a + b x] Log[1 - -------] + PolyLog[2, -------]
                         2 a                   2 a
-(---------------------------------------------------)
                           b
Time to compute: 0.03 second
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