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(-(a*Log[a - b*x]) + b*x*(-Log[x] + Log[-a + b*x]))/(a*x)


Integrate[Log[a - b*x]/x^2, x] ==
(-(a*Log[a - b*x]) + b*x*(-Log[x] + Log[-a + b*x]))/ (a*x)



          Log[a - b x]
Integrate[------------, x] == 
                2
               x

-(a Log[a - b x]) + b x (-Log[x] + Log[-a + b x])
-------------------------------------------------
                       a x

Time to compute: 0.01 second

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