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(Log[1 + (2*x)/3]*Log[x] + PolyLog[2, (-2*x)/3])/2


Integrate[Log[x]/(3 + 2*x), x] ==
(Log[1 + (2*x)/3]*Log[x] + PolyLog[2, (-2*x)/3])/2



          Log[x]
Integrate[-------, x] == 
          3 + 2 x

        2 x                      -2 x
Log[1 + ---] Log[x] + PolyLog[2, ----]
         3                        3
--------------------------------------
                  2

Time to compute: 0.01 second

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