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((x*Log[x])/(b + a*x) - Log[b + a*x]/a)/b


Integrate[Log[x]/(b + a*x)^2, x] ==
((x*Log[x])/(b + a*x) - Log[b + a*x]/a)/b



            Log[x]
Integrate[----------, x] == 
                   2
          (b + a x)

x Log[x]   Log[b + a x]
-------- - ------------
b + a x         a
-----------------------
           b

Time to compute: 0.02 second

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