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x*(2 + (-2 + Log[x])*Log[x])


Integrate[Log[x]^2, x] ==
x*(2 + (-2 + Log[x])*Log[x])



                2
Integrate[Log[x] , x] == 

x (2 + (-2 + Log[x]) Log[x])

Time to compute: < 0.01 second

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