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Log[x]^(1 + n)/(1 + n)


Integrate[Log[x]^n/x, x] ==
Log[x]^(1 + n)/(1 + n)



                n
          Log[x]
Integrate[-------, x] == 
             x

      1 + n
Log[x]
-----------
   1 + n

Time to compute: < 0.01 second

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