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(6 + 4*x - Sin[6 + 4*x])/8


Integrate[Sin[3 + 2*x]^2, x] ==
(6 + 4*x - Sin[6 + 4*x])/8



                      2
Integrate[Sin[3 + 2 x] , x] == 

6 + 4 x - Sin[6 + 4 x]
----------------------
          8

Time to compute: 0.03 second

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