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(3*x)/8 - Sin[2*a*x]/(4*a) + Sin[4*a*x]/(32*a)


Integrate[Sin[a*x]^4, x] ==
(3*x)/8 - Sin[2*a*x]/(4*a) + Sin[4*a*x]/(32*a)



                  4
Integrate[Sin[a x] , x] == 

3 x   Sin[2 a x]   Sin[4 a x]
--- - ---------- + ----------
 8       4 a          32 a

Time to compute: < 0.01 second

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