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(x*Sqrt[-16 + x^2])/2 - 8*Log[2*(x + Sqrt[-16 + x^2])]


Integrate[Sqrt[-16 + x^2], x] ==
(x*Sqrt[-16 + x^2])/2 - 8*Log[2*(x + Sqrt[-16 + x^2])]



                      2
Integrate[Sqrt[-16 + x ], x] == 

              2
x Sqrt[-16 + x ]                            2
---------------- - 8 Log[2 (x + Sqrt[-16 + x ])]
       2

Time to compute: 0.02 second

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