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(b^x*c^(d*x)*E^(a*x))/(a + Log[b] + d*Log[c])

Integrate[b^x*c^(d*x)*E^(a*x), x] ==
(b^x*c^(d*x)*E^(a*x))/(a + Log[b] + d*Log[c]) 

           x  d x  a x
Integrate[b  c    E   , x] == 

     x  d x  a x
    b  c    E
---------------------
a + Log[b] + d Log[c]
Time to compute: 0.01 second
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