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(2*Log[-2 - x] + Log[-1 + x])/3


Integrate[x/((-1 + x)*(2 + x)), x] ==
(2*Log[-2 - x] + Log[-1 + x])/3



                 x
Integrate[----------------, x] == 
          (-1 + x) (2 + x)

2 Log[-2 - x] + Log[-1 + x]
---------------------------
             3

Time to compute: < 0.01 second

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