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((1 + 2*x)^(-1) + Log[2 + 4*x])/16


Integrate[x/(4*x + 2)^2, x] ==
((1 + 2*x)^(-1) + Log[2 + 4*x])/16



              x
Integrate[----------, x] == 
                   2
          (4 x + 2)

   1
------- + Log[2 + 4 x]
1 + 2 x
----------------------
          16

Time to compute: 0.01 second

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