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(a/(a + b*x) + Log[a + b*x])/b^2


Integrate[x/(a + b*x)^2, x] ==
(a/(a + b*x) + Log[a + b*x])/b^2



              x
Integrate[----------, x] == 
                   2
          (a + b x)

   a
------- + Log[a + b x]
a + b x
----------------------
           2
          b

Time to compute: 0.02 second

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