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(b*x - a*Log[a + b*x])/b^2

Integrate[x/(a + b*x), x] ==
(b*x - a*Log[a + b*x])/b^2 

             x
Integrate[-------, x] == 
          a + b x

b x - a Log[a + b x]
--------------------
          2
         b
Time to compute: < 0.01 second
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