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(2*x*(1 + x) - (1 + 2*x)*Log[2 + 4*x])/(16 + 32*x)


Integrate[x^2/(4*x + 2)^2, x] ==
(2*x*(1 + x) - (1 + 2*x)*Log[2 + 4*x])/(16 + 32*x)



               2
              x
Integrate[----------, x] == 
                   2
          (4 x + 2)

2 x (1 + x) - (1 + 2 x) Log[2 + 4 x]
------------------------------------
             16 + 32 x

Time to compute: 0.02 second

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