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(x*(1 + x))/(8 + 16*x) - Log[2 + 4*x]/16

Integrate[x^2/(4*x + 2)^2, x] ==
(x*(1 + x))/(8 + 16*x) - Log[2 + 4*x]/16 

               2
              x
Integrate[----------, x] == 
                   2
          (4 x + 2)

x (1 + x)   Log[2 + 4 x]
--------- - ------------
8 + 16 x         16
Time to compute: 0.02 second
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