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ExpIntegralEi[3*(a + Log[x])]/E^(3*a)

Integrate[x^2/(a + Log[x]), x] ==
ExpIntegralEi[3*(a + Log[x])]/E^(3*a) 

               2
              x
Integrate[----------, x] == 
          a + Log[x]

ExpIntegralEi[3 (a + Log[x])]
-----------------------------
             3 a
            E
Time to compute: 0.02 second
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