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(b*x - a^2/(a + b*x) - 2*a*Log[a + b*x])/b^3


Integrate[x^2/(a + b*x)^2, x] ==
(b*x - a^2/(a + b*x) - 2*a*Log[a + b*x])/b^3



               2
              x
Integrate[----------, x] == 
                   2
          (a + b x)

         2
        a
b x - ------- - 2 a Log[a + b x]
      a + b x
--------------------------------
                3
               b

Time to compute: 0.03 second

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