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(x^(1 + p)*(-1 + (1 + p)*Log[x]))/(1 + p)^2


Integrate[x^p*Log[x], x] ==
(x^(1 + p)*(-1 + (1 + p)*Log[x]))/(1 + p)^2



           p
Integrate[x  Log[x], x] == 

 1 + p
x      (-1 + (1 + p) Log[x])
----------------------------
                 2
          (1 + p)

Time to compute: 0.02 second

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