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x^2/2 + (x*Log[x])/Sqrt[x^2]


Integrate[x + 1/Sqrt[x^2], x] ==
x^2/2 + (x*Log[x])/Sqrt[x^2]



                 1
Integrate[x + --------, x] == 
                    2
              Sqrt[x ]

 2
x    x Log[x]
-- + --------
2          2
     Sqrt[x ]

Time to compute: 0.03 second

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